-b^2-2b-7=-6

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Solution for -b^2-2b-7=-6 equation: 



-b^2-2b-7=-6

We move all terms to the left:

-b^2-2b-7-(-6)=0

We add all the numbers together, and all the variables

-1b^2-2b-1=0

a = -1; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{2}{-2}=-1$

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